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Energy Optimization Savings Example

20kW Motor Running at 20% Load

 

This diagram shows a 20kW motor that is running at 20% of its full load capacity. The application is calculated to be losing 0.6kW per hour through the heat generated. in the motor windings, plus an additional 2.6 KW per hour through iron losses in the motor. The total efficiency of the application is shown as 54%.

 

20kW Motor Running at 20% Load with a Baldor Digital Soft-Starter

 

Saving 1.8kWh every hour while on part load!

This example shows how the energy optimizing system reduces the energy consumed. Once the optimizing process takes place, the heat generated is reduced to 0.4kW per hour and the iron losses of the motor reduced to 1 kW per hour. The total efficiency of the application is shown as 71%.

In this example, the optimizing system would produce a saving of 1.8 kW per hour.

The annual savings amount that could be achieved for this reduction based on 0.10 $/kWh is as follows:

 
% Time
Partial Load
Annual Hours
at Part Load
kWh
Saving
Annual
Savings
40% 3,494 6,289 $630
60% 5,241 9,434 $943
80% 6,988 12,578 $1,260


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